# whether the adhering to collection merge or deviate

Answers: 2

You can make use of the comparison test :

\[\sum_{n=1}^\infty \frac{1}{2^n 3^{n-1}}<\sum_{n=1}^\infty \frac{1}{2^n}=1.\]

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Douglas S. Stones 2019-12-03 04:25:38

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