Roots of parabola

I have a parabola with the formula $y = x^2 + 6x + 7$ and also I am attempting to compute the $x$ - obstruct factors.

Below is my functioning until now

  1. allow $y = 0$,
  2. $x^2 + 6x + 7 = 0$
  3. $x(x + 6) = -7$

After this I have no suggestion where to go next. Any kind of aid is valued.

3
2022-06-07 14:35:59
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Answers: 1

You need to possibly locate the origins by utilizing this formula. For a square formula $ax^{2}+bx+c$ we have the origin is as: $$x = \frac{-b \pm \sqrt{D}}{2a}$$

where $D$ is the discriminant offered by $D=b^{2}-4ac$. So in your instance note that $a=1$, $b=6$ and also $c=7$. Hope you can locate your means from below. So $D=6^{2}-4\times 7 \times 1=8$. So you have the value of the origins as: $$ x= \frac{-6 \pm \sqrt{8}}{2 \times 1} = \frac{-6 \pm 2\sqrt{2}}{2} = -3 \pm \sqrt{2}$$

For even more details pertaining to Quadratic Equations Please see:

Here favors just how your parabola will resemble:

5
2022-06-07 14:58:22
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