alternative on Sierpinski carpeting: rescue the table linen!

I was experimenting with Sierpinski carpets (see pretty GPU-produced picture here), and also thought of a variant that I have actually been incapable to locate stated in other places. I'm asking yourself if any person can inform me an existing name for it, and also aid me establish where it matches existing categories of fractals.

As you possibly recognize,

The building and construction of the Sierpinski carpeting starts with a square. The square is reduced right into 9 conforming subsquares in a 3 - by - 3 grid, and also the [open ] main subsquare is gotten rid of. The very same procedure is after that used recursively to the continuing to be 8 subsquares, advertisement infinitum.

In this variant, as opposed to just getting rid of the main subsquare, we recursively use the very same procedure to it "vice versa." (Is there a far better term for that?) That is, we deal with the main opening as if we intend to change it with the enhance of [this version of ] a Sierpinski carpeting.

So when we reoccur on the main opening, we placed an "anti - opening" (like a "donut opening" without a donut) in the center of it. We will certainly after that reoccur on the anti - opening making use of the regular (favorable) procedure, and also reoccur on the 8 subsquares bordering the anti - opening making use of the inverted procedure.

It looks something similar to this, in its 5th model:

If you assume I need to upload the code for this, I'm satisfied to, yet I really did not assume it was really pertinent to the mathematics inquiry.

I've been calling it "Sierpinski table linen" given that I could not locate an additional name for it, and also due to the fact that it advises me of a shoelace or crocheted table linen layout.

Improvement: @Rahul mentioned that "the restricting set of the recursive procedure does not exist." This is due to the fact that the main factor of the device square have to become part of both the table linen and also its enhance, or neither - which is difficult. (Of training course we can still do limited models of the positive procedure without striking an opposition.)

To repair this trouble, I attempted recommending that we specify the table linen set T (randomly) to include the main factor. The main subsquare is changed with the union of the main factor with the scaled - down enhance of T. As in the past, the subsquares around the facility are changed with scaled - down duplicates of T (and also consequently the main factor of each of the subsquares is had in T).

An additional upgrade: Unfortunately the very same trouble holds true of any kind of factor with an illogical coordinate, and also of several sensible ones. If we share the works with in base 3, similar to the Cantor set, a factor belongs to T iff the variety of 1 remains in the base - 3 development of each of its works with is also. Yet this does not benefit numbers with duplicating 1's.

If we attempted to repair this by making all "trouble factors" come from T, we would certainly be entrusted "virtually" a strong device square, minus a "dirt" of sensible factors with an also variety of 1 remains in their base - 3 coordinate developments. After that T would certainly discontinue to create intriguing fractal images (in the restriction). Its location would certainly be 1, like the irrationals$^2$. It is unclear to me that T would certainly be various from the set of the irrationals$^2$ in any kind of intriguing means.

Mind you, we can still attract images of the umpteenth model of the table linen that are enjoyable to consider, yet it sheds a bargain of its bite if it does not exist as a fractal.

Can you consider a means to conserve the table linen from termination as a fractal?

The remainder of this inquiry was created under the misapprehension that the table linen exists (is a well - specified set) in the restriction.

Fractal measurement

The typical carpeting has Hausdorff dimension

$log(8)/log(3) = ~1.8928$

stemmed from the reality that it takes 8 self - comparable duplicates at decrease variable 1/ 3 to cover itself (see example for Sierpinski triangle). In this blood vessel I figure that the table linen takes 9 self - comparable duplicates at decrease variable 1/ 3 to cover itself (no smaller sized duplicate will cover the center mini - square), so it would certainly have Hausdorff measurement

$log(9)/log(3) = 2$

This would certainly place it in the very same firm (in regards to Hausdorff measurement) as room - loading contours like the Sierpinski contour, Hilbert, Peano, etc Does this audio practical until now?

I'm not fairly comfy with that said, however, due to the fact that a 1/ 3 - dimension duplicate of the table linen will certainly not in fact cover the entire center subsquare. Actually I can not see just how any kind of limited variety of lowered - dimension duplicates of the table linen would certainly cover the entire center subsquare. And also if we claim we require a boundless number, the Hausdorff measurement would certainly be infinite.: - (

As a choice, I took into consideration multifractals, given that we appear to have various scaling actions taking place in various components of the attractor. Yet that is much deeper water than I'm ready to fall to.

  • Can any person aim me to literary works on fractals that are specified making use of enhances of lowered - dimension self - comparable collections (along with the common lowered - dimension self - comparable collections)? Is that a class of fractals that has been researched? (Update Or are such "fractals" destined be ill - specified (self - contradictory) by their nature?

In a similar way to Hausdorff measurement, the box - counting measurement (making use of the standard "if the room were separated up right into a grid of boxes of dimension ε, the amount of boxes of that range would certainly have component of the attractor?") additionally appears to wind up at 2, for similar factors. And also I'm extra comfy with it due to the fact that a "box" (in contrast to a lowered duplicate of the table linen) will certainly without a doubt cover the entire center subsquare. It appears clear that in the restriction, package - counting measurement merges to 2, due to the fact that there are no voids, so every box, at whatever dimension ε, will certainly constantly have component of the fractal.

In regards to location (typical Lebesgue measure), I'm rather certain that the table linen has absolutely no, like the carpeting, due to the fact that it has no periods (rectangular shapes) that are totally in the set. Right? ( Update: I stand dealt with: the table linen appears to have location 1/ 2.)


There are numerous inquiries over, so to link them entirely: I'm asking yourself if this table linen version is something new and also intriguing, or something well - recognized, or an unidentified yet unimportant version that can be identified under existing groups. E.g. if there is a version of the Cantor set that is specified in a similar way to the table linen (for one measurement), I would certainly value a link to details concerning that.

(Update One point that appears intriguing to me concerning it is that it has factors in every period of the device square, yet it additionally has openings in every period. I presume it resembles sensible numbers in [0,1 ] because respect, or like room - loading curves/trees, yet is not a contour or tree (not attached). I can not consider various other fractals off - hand that resemble that, can you? It appears that this building is gotten in touch with the reality that we reoccur on the inverted as opposed to leaving openings.

P.S. I simply reviewed the term equally thick (Interleaving Ad Infinitum): 'If a set S with straight getting O can be separated right into 2 parts An and also B such that in between every 2 distinctive components of A is a component of B, and also the other way around, after that the collections An and also B are claimed to be "equally thick".' So the table linen and also its enhance are equally thick, thinking that this term can be generalised to the device square. At the very least in any kind of straight or upright straight piece of the device square, they are equally thick.

2019-05-18 23:58:02
Source Share
Answers: 3

Regarding your upgrade: Using Conway's base 13 function or various other building and constructions (I have one I favor) you can locate a function $f: (0,1) \rightarrow (0,1)$ such that for any kind of period $(a,b) \subset (0,1)$ and also $y \in (0,1)$ there is an $x \in (a,b)$ such that $f(x)=y$. After that for offered $y$ the factors such that $f(x)=y$ are thick in $(0,1)$. So you have continuum several disjoint collections, each thick in $(0,1)$.

2019-05-21 12:37:20

I created a number of things concerning the buildings of this set thinking it existed, after that I understood that it had not been also noticeable that the set was well - specified.

Below is the trouble: Does the main factor come from the set? If it does, after that it does not come from the center block, and also the other way around, bring about an opposition. So the restricting set of the recursive procedure does not exist.

Nonetheless, considering the image, it really feels as though the restriction "needs to" exist in some increased feeling. This can perhaps be connected to the manner in which some series of features which do not merge to features do in fact merge to circulations. Or I can simply be incorrect and also the restriction merely can not exist in any kind of feeling. Edit: Well, it ends up that the restricting action had in any kind of rectangle-shaped area is simply half the location of the rectangular shape. So I intend it does have a restriction in the feeling of an action on $[0,1]^2$, yet it is not a really intriguing action.

The noticeable equivalent variation of the Cantor set would certainly be to change every center 3rd with the enhance of the set, as opposed to leaving it vacant. Nonetheless, the Cantor set has a really wonderful analysis in regards to ternary developments: an actual number $x \in [0,1]$ remains in the Cantor set if and also just if its ternary development has no figure 1 (permitting, as an example, $1/3 = 0.1_3$ to be $0.0222\ldots_3$). For this version, the equivalent problem would certainly need to be that the ternary development has an also variety of ones. This is well - specified for portions of the kind $a/3^b$ whose ternary development ends, yet like above, it is unclear just how to manage rationals like $1/2$, or all the irrationals.

2019-05-21 12:24:01

The location, if it exists, is $\frac12$. Allow the location inside the device square be A. After that it is composed of $8$ duplicates at $\frac13$ straight dimension, plus the enhance of a $\frac13$ straight dimension duplicate (the facility square). So $A=\frac89A+\frac{1-A}{9}$. There is no worry having a location without a rectangular shape. See the Fat Cantor Set. I think having favorable location additionally sustains measurement $2$.

2019-05-21 10:42:09