Exist extra sensible numbers than integers?
I've been informed that there are specifically the very same variety of rationals as there are of integers. The set of rationals is countably boundless, consequently every sensible can be related to a favorable integer, consequently there coincide variety of rationals as integers. I've overlooked signrelated concerns, yet these are conveniently taken care of.
To count the rationals, take into consideration collections of rationals where the and also numerator declare and also amount to some constant. If the constant is 2 there's 1/1. If the constant is 3, there's 1/2 and also 2/1. If the constant is 4 there's 1/3, 2/2 and also 3/1. Until now we have actually suspended 6 rationals, and also if we proceed enough time, we will at some point count to any kind of details sensible you like state.
The problem is, I locate this really tough to approve. I have 2 factors. First, this reasoning appears to think that infinity is a limited number. You can count to and also number any kind of sensible, yet you can not number all rationals. You can not also count all favorable integers. Infinity is code for "despite just how much you count, you have actually never ever counted sufficient". If it were feasible to count to infinity, it would certainly be feasible to count one action much less and also stop at matter infinity1 which have to be various to infinity.
The 2nd factor is that it's really simple to construct different mappings. In between absolutely no and also one there are definitely several sensible numbers, in between one and also 2 there are definitely several sensible numbers, and more. To me, this appears a far more practical strategy, indicating that there are boundless sensible numbers for every single integer.
Yet also after that, this is simply among several different means to map in between series of rationals and also series of integers. Given that you can count the rationals, you can just as count tipping by any kind of quantity for each and every sensible. You can make use of 1..10 for the first sensible and also 11..20 for the 2nd and so on. Or 1..100 and also 101..200 etc, or 1..1000 and also 1001..2000 and so on. You can map limited series of integers of any kind of dimension per sensible in this manner and also, given that there is no limited upper bound to the tipping quantity, you can say there are possibly boundless integers for every single solitary sensible.
So ... can any person encourage me that there is a solitary distinct proper response to this inquiry? Exist extra sensible numbers than integers, or otherwise?
MODIFY
Although I've currently approved a solution, I'll simply add some added context.
My factor for examining this connects to the Hilbert spacefilling contour. I locate this intriguing as a result of applications to multidimensional indexing information frameworks in software program. Nonetheless, I located Hilberts case that the Hilbert contour essentially loaded a multidimensional room tough to approve.
As stated in a comment listed below, a one meter line sector and also a 2 meter line sector can both be viewed as collections of factors and also, yet (by the reasoning in solutions listed below), those 2 collections are both the very same dimension (cardinality). Yet we would certainly not assert both line sectors are both the very same dimension. The sizes are limited and also various. Surpassing this, we most absolutely would not assert that the dimension of any kind of limited straight line sector amounts to the dimension of a onemeterbyonemeter square.
The Hilbert contour thinking makes good sense currently  the set of factors in the contour amounts to the set of factors in the room it loads. Formerly, I was assuming way too much concerning standard geometry, and also could not approve the dimension of a contour as amounting to the dimension of a room. Nonetheless, this isn't based upon a fallacious countingtoinfinity argument  it's an essential effect of a different logic. Both constructs are equivalent due to the fact that they both stand for the very same set of factors. The area/volume/etc of the contour adheres to from that.
You can think of it a various means. Take into consideration the set of actual numbers in between 0 and also 1, and afterwards the set of actual numbers in between 0 and also 2.
By instinct, it appears that the set of actual numbers in between 0 and also 2 has double the dimension of the set in between 0 and also 1. Nonetheless, this is not the instance, due to the fact that both collections have the very same cardinality .
Take into consideration the function $f(x) = 2x$. Every actual in between 0 and also 1 is bijected to an actual in between 0 and also 2. Consequently the collections are of the very same dimension.
The cardinality of the set of rationals coincides as the cardinality of the integers coincides as the cardinality of the allnatural numbers.
When we count a limited set of components, we are creating a oneone map from the set onto a limited first sector of the allnatural numbers. If we need to know if 2 limited collections have the very same cardinality (are equicardinal) we can either : 1) matter both collections and also see if we get the very same number, or 2) effort to construct a oneone map from one set onto the various other. If we can construct the map focused on in (2 ), after that the collections are equicardinal.
Generalising that procedure from the limited collections to approximate collections, we get that for any kind of 2 collections, the collections have the very same cardinality (are equicardinal) if there exists a bijection (a oneone map in between the collections that is onto the target as opposed to just right into). For the limited instance, if there is a oneone map that is a bijection, all oneone maps are bijective. That is not the instance for boundless collections, which is the origin of your 2nd problem.
To resolve that 2nd problem, take into consideration the map from the adverse integers to the favorable integers which maps each adverse integer to its outright value. The presence of that map reveals that both collections are equicardinal. We can, certainly, construct oneone maps from the adverse integers to the favorable integers that enjoy as opposed to on. (Consider the map that takes each adverse integer to its item with 2.) Yet, the presence of these different maps does not influence the reality that there goes to the very least one bijection in between the collections, which is all it considers those collections to be equicardinal.
When it comes to your first problem, I do not see why you assume the procedure thinks that "infinity is a limited number". What it entails is defining a mapping function from one set to the various other that is oneone and also onto. That effort can absolutely fall short, as Cantor's Diagonalization Argument that the cardinality of a set is constantly purely much less than the cardinality of its power set programs. (A pertinent application of that strategy is the popular evidence that the cardinality of the reals is more than the cardinality of the allnatural numbers.)
In maths a set is called boundless if it can be taken into a 11 document with a correct part of it, and also limited it is not boundless. (I recognize it appears insane to have the principle of boundless as primitive and also limited as a derivate, yet it's less complex to do this, given that or else you have to think that the integers exist prior to claiming that a set is limited)
As for your statements :  with your method (if you do not neglect to throw away portions like 4/6 which amounts to 2/3) you in fact counted the rationals, given that for each and every number you have a function which links it to an allnatural number. It's real that you can not count ALL rationals, or all integers ; yet you can nor attract an entire straight line, can you?  with boundless collections you might construct boundless mappings, yet you simply require a solitary 11 mapping to show that 2 collections are equivalent.
You might not be really completely satisfied with this solution, yet I'll attempt to clarify anyhow.
Countability. We're not actually speaking about whether you can "count every one of the rationals", making use of some limited procedure. Clearly, if there is a boundless variety of components, you can not count them in a limited quantity of time making use of any kind of practical procedure. The inquiry is whether there is the very same number of rationals as there declare integers ; this is what it suggests for a readied to be "countable" for there to exist a onetoone mapping from the favorable integers to the embeded in inquiry. You have actually defined such a mapping, and also consequently the rationals are "countable". (You might differ with the terms, yet this does not influence whether the principle that it classifies is systematic.)
Different mappings. You appear to be disappointed with the reality that, unlike the instance of a limited set, you can specify a shot from the allnatural numbers to the rationals which is not surjective that you can actually specify an extra basic relationship in which each integer is connected to definitely several rationals, yet no 2 integers relate to the very same sensible numbers. Well, 2 can dip into that video game : you can specify a relationship in which every sensible number is connected to definitely several integers, and also no 2 rationals relate to the very same integers! Simply specify the relationship that each favorable sensible a/b is connected to all numbers which are divisible by 2 ^{a } yet not 2 ^{a +1 }, and also by 3 ^{b } yet not 3 ^{b +1 } ; or even more usually specifically 2 ^{ka } and also 3 ^{kb } for any kind of favorable integer k. (There are, as you claim, authorize concerns, yet these can be smoothed away.)
You could whine that the relationship I've specified isn't "allnatural". Probably you desire the reality that the integers are a part of the rationals a subgroup, actually, taking both of them as additive teams which the variable team ℚ/ ℤ is boundless. Well, this is most definitely intriguing, and also it's an allnatural type of framework to be curious about. Yet it's greater than what the concern of "plain cardinality" is attempting to access : set concept wants dimension no matter framework, therefore we do not limit to maps which have one or an additional sort of "simplicity" concerning them. Certainly, if you want mappings which value some type of framework, you can construct concepts of dimension based upon that : this is what is carried out in action concept (with action), straight algebra (with measurement), and also without a doubt team concept (with index). So if you do not such as cardinality as set philosophers develop it, you can consider even more organized actions of dimension that you locate extra intriguing!
Immediate precursors. A rather unconnected (yet still vital) issue that you make is this :" If it were feasible to count to infinity, it would certainly be feasible to count one action much less and also stop at matter infinity1 which have to be various to infinity. " The inquiry is : why would certainly you always have the ability to stop at 'infinity minus one'? This holds true for limited collections, yet it does not always hold that anything which holds true of limited collections holds true additionally for boundless ones. (In reality, clearly, some points always will fall short.) This is necessary if you research ordinals, which mirrors the procedure of counting itself somehow (labelling points as being "first", "2nd", "3rd", etc), as a result of the principle of a restriction ordinal : the first "infinitieth" component of a wellordering does not have any kind of prompt precursors! Once more, you are free to claim that these are principles that you are not curious about discovering directly, yet this does not suggest that they are always mute.
To sum up : the set philosophers gauge "the dimension of a set" making use of a straightforward definition which does not respect framework, and also which might breach your instincts if you such as to take the framework of the integers (and also the sensible numbers) really seriously, as well as additionally intend to maintain your instincts concerning limited collections. There are 2 remedies to this : attempt to extend your instinct to accomodate the suggestions of the set philosophers, or research a various branch of mathematics which you locate extra intriguing!
Mathematicians have really specific interpretations for terms like "boundless" and also "very same dimension". The solitary distinct proper response to this inquiry is that making use of the typical mathematical interpretations, the rationals have the "very same dimension" as the integers.
First, below are the interpretations :

Define "0" = emptyset, "1" = 0, "2" = 0,1, "3" = 0,1,2, and so on. So, the number "n" is actually a set with "n" components in it.

A set A is called "limited" iff there is some n and also a function f :A > n which is bijective.

A set A is called "boundless" iff it is not limited. (Keep in mind that this idea claims absolutely nothing concerning "counting never ever quits" or anything like that. )

2 collections An and also B are claimed to have the "very same dimension" if there is a some function f :A > B which is a bijection. Keep in mind that we do NOT call for that ALL features be bijections, simply that there is SOME bijection.
As soon as one approves these interpretations, one can confirm that the rationals and also integers have the very same dimension. One simply requires to locate a certain bijection in between both collections. If you do not such as the one you stated in your blog post, may I recommend that CalkinWilf enumeration of the rationals? (Merely google search Calkin Wilf counting rationals. The first.pdf has what I'm speaking about ).
Certainly, these offer bijections in between the naturals (with out 0 ) and also the rationals, once you have a bijection similar to this, it's very easy to construct a bijection from the integers to the rationals by making up with a bijection from the naturals to the integers.