Run a shell script using cron

I have this FeedIndexer.sh:

#!/bin/sh java -jar FeedIndexer.jar

Just to run FeedIndexer.jar which remains in the very same directory site as the .sh, I would love to run it making use of crontab, so I did this:

# /etc/crontab: system-wide crontab
# Unlike any other crontab you don't have to run the `crontab'
# command to install the new version when you edit this file
# and files in /etc/cron.d. These files also have username fields,
# that none of the other crontabs do.

SHELL=/bin/sh
PATH=/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin

# m h dom mon dow user command
17 * * * * root    cd / && run-parts --report /etc/cron.hourly
25 6 * * * root test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.daily )
47 6 * * 7 root test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.weekly )
52 6 1 * * root test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.monthly )
01 01 * * * root run-parts --report /home/slosada/workspace/FeedIndexer/target/FeedIndexer.sh
#

But I do not recognize just how to run it. Have I made any kind of blunder?

0
2022-07-25 20:40:13
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